I’m sorry I’ve done it now..
But I will answer anyway..
Write the general term.
Tr+1= 1024Cr.(51/2)1024-r.(71/8)r
Now 1024Cr is always an integer..
We have to check for (1024-r)/2 and r/8 to be integer. .we can see that the no has to be divisble by 8 and yet it has to be an even number too...
Simply we see the maximum multipliation of 8 for which it is valid which is 129... because 8*130=1040.
Thank you