Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
`        No of six digit number that can be formed, having the property that every succeeding digit is greater than the preceding digit, is equal to? `
8 months ago

## Answers : (2)

Saurabh Koranglekar
askIITians Faculty
1857 Points
```							the first digit can be selected in 9 waysnext in 8 ways and so ontherefore total ways = 9*8*7*6*5*4
```
8 months ago
Arun
20299 Points
```							Once you pick six different digits, there is only one way to arrange them so that the digits are increasing. I would view the answer as 9C6, but of course this is equal to 9C3 nCr = nC(n-r) 9C6 = 9C3 = 84
```
8 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Algebra

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions

## Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details