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Grade 11Algebra

No of six digit number that can be formed, having the property that every succeeding digit is greater than the preceding digit, is equal to?

Profile image of Harshita
7 Years agoGrade 11
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2 Answers

Profile image of Saurabh Koranglekar
7 Years ago

the first digit can be selected in 9 ways
next in 8 ways and so on
therefore total ways = 9*8*7*6*5*4
Profile image of Arun
7 Years ago
Once you pick six different digits, there is only one way to arrange them so that the digits are increasing. I would view the answer as 9C6, but of course this is equal to 9C3 

nCr = nC(n-r) 
9C6 = 9C3 = 84 

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