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`        No of six digit number that can be formed, having the property that every succeeding digit is greater than the preceding digit, is equal to? `
one year ago

Saurabh Koranglekar
6801 Points
```							the first digit can be selected in 9 waysnext in 8 ways and so ontherefore total ways = 9*8*7*6*5*4
```
one year ago
Arun
24498 Points
```							Once you pick six different digits, there is only one way to arrange them so that the digits are increasing. I would view the answer as 9C6, but of course this is equal to 9C3 nCr = nC(n-r) 9C6 = 9C3 = 84
```
one year ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions