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modulus operator is a bit tough for me and i cant understand a thing in some questions for eg lim x->0- mod(x)/x=-1; how does this work mod must always be positive right?

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4 years ago

```							Its not difficult if you visualise it graphically.  Search google for desmos graphing calculator and plot the graph for this function y= mod(x)/x.You will see why left hand limit for thins function is -1 at 0. Aletrnate solution 2by definition mod(x) = x if x> 0 and                                = -x if x Hence for xor limit x->0- = -1. Alternate solution2let x =0-has h->0 x->0-hence the given limit can we evalauted aslimit h->0  mod (h)/(-h) = -1. Its as simple as that
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4 years ago
```							Posting again as the there is bug in website which does not properly dispay inequalities. Its not difficult if you visualise it graphically.  Search google for desmos graphing calculator and plot the graph for this function y= mod(x)/x.You will see why left hand limit for this function is -1 at 0. Alternate solution 1by definition mod(x) = x if x is greater than 0                                = -x if x is less than 0Hence for x less than 0mod(x)/x = -x/x = -1.or limit x->0- = -1. Alternate solution2let x =0-has h->0 x->0-hence the given limit can we evalauted aslimit h->0  mod (h)/(-h) = -1. Its as simple as that
```
4 years ago
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