Michael finished colouring a picture in (7/12) hour. Vaibhav finished colouring the same picture in (3/4) hour. Who worked longer? By what fraction was it longer?

Dear Student

From the question, it is given that,
Time taken by the Michael to colour the picture is = (7/12)
Time taken by the Vaibhav to colour the picture is = (3/4)
The LCM of 12, 4 = 12
Now, let us change each of the given fraction into an equivalent fraction having 12 as the denominator.
(7/12)
= (7/12) × (1/1)
= 7/12
(3/4) = (3/4) × (3/3) = 9/12
Clearly, (7/12) < (9/12)
Hence, (7/12) < (3/4)
Thus,
Vaibhav worked for longer time.
So, Vaibhav worked longer time by = (3/4)–(7/12)
= (9/12)–(7/12)
= (9 - 7)/12
= (2/12)
= (1/6) of an hour.

Thanks