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Log7log7√7(√7√7)

Log7log7√7(√7√7)

Grade:11

1 Answers

Ravi
askIITians Faculty 69 Points
7 years ago
Start from the most complex root over root...
As the base is same, assign each ‘7’ their individual powers to which they are raised. If a specific base is assigned, for instance base 7, sum the power, bring the power in multiplication with the log7(in the interior of first log). Proceed to get a simplifoed solution as the log77 will be 1 and log1 will be 0.

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