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`        (log x base 2)^2 – log x^3 base 2 = 4, how can i solve this equation?`
2 years ago

Arun
23342 Points
```							Dear student Let log x base 2 = t Thent² -3t = 4t² -3t -4 = 0(t -4)(t +1) = 0t = 4 and t = -1 NowLog x base 2 = 4x = 2⁴ = 16 NowLog x base 2 = -1x = 2^-1 = ½  RegardsArun (askIITians forum expert)
```
2 years ago
ankush rathee
36 Points
```							Let (log 2 x) be a So a^2-3a-4=0So (a-4)(a+1)=0So a=4,a=-1So log 2 x=4So x=2^4=16So log 2 x=-1So 2^-1=XX=2^-1=1/2
```
2 years ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions