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Log(tan18)+log(tan36)+log(tan54)+log(tan72)=? Please say me the answer

Log(tan18)+log(tan36)+log(tan54)+log(tan72)=?
Please say me the answer

Grade:11

1 Answers

Ayushi nanda
15 Points
5 years ago
log(tan 18)+log(tan 36)+log(tan 54)+log(tan 72)Using log(a)+log(b)+,,,=log(ab...), we getlog(tan 18)+log(tan 36)+log(tan 54)+log(tan 72)=log[tan 18.tan 36.tan 54.tan 72]=log[tan 18.tan 36.cot (9054).cot (9072)]=log[tan 18.tan 36.cot 36.cot 18]=log[tan 18.tan 36.1tan18.1tan 36]=log(1)=0 [Answer]

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