Algebra
{log(sec x – tan x)}^3 = [log{1/(sec x + tan x )}]^3How??Please show the steps.
{log(sec x – tan x)}^3 = [log{1/(sec x + tan x )}]^3
How??Please show the steps.
1 Answer
Arun
Dear student
We can write
Sec x - tan x = 1/(sec x + tanx)
Hence it can also be proved
Hope it helps
Regards
Arun (askIITians forum expert)
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