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{log(sec x – tan x)}^3 = [log{1/(sec x + tan x )}]^3 How??Please show the steps.

{log(sec x – tan x)}^3 =  [log{1/(sec x + tan x )}]^3
How??Please show the steps.

Grade:

1 Answers

Arun
25750 Points
5 years ago
Dear student
 
We can write 
Sec x - tan x = 1/(sec x + tanx)
 
Hence it can also be proved
 
Hope it helps
 
Regards
Arun (askIITians forum expert)

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