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let PS be the median of the triangle with vertices P(2,2),Q(6,-1)and R(7,3).the equation of the line passing through (1,-1) and parallel to PS is
coordinate of S=(13/2,1)slope of ps=(1-2)/13/2 -2)=(-1)/(9/2)=-2/9Eq. of the line passing through (-1,1) and parallel to PS isy-1=(-2/9)(x+1)9(y-1)=-2x-29y-9+2x+2=02x+9y-7=0Thanks & RegardsRinkoo GuptaAskIITians Faculty
coordinate of S=(13/2,1)slope of ps=(1-2)/13/2 -2)=(-1)/(9/2)=-2/9Eq. of the line passing through (-1,1) and parallel to PS isy+1=(-2/9)(x-1)9(y+1)=-2x+29y+9+2x-2=02x+9y+7=0A little correction but a big difference.
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