Let p,q ,r be the elements of R , and r p0. If the quadratic equation p(x^2) + qx +r = 0 has two complex roots a and b then |a| + |b| is..

Question

Let p,q ,r be the elements of R , and r >p>0. If the quadratic equation p(x^2) + qx +r = 0 has two complex roots a and b then |a| + |b| is..

Aditya Gupta · Answer

obviously b=a conjugate so |a| + |b|= 2|a| (as modulus of conjugate=modulus of complex no) now, q^2 – 4pr then x=[ –q+-m*i]/2p |x|=root(q^2+m^2)/2p=root(4pr)/2p =root(r/p) so |a| + |b|=2root(r/p)

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Let p,q ,r be the elements of R , and r >p>0. If the quadratic equation p(x^2) + qx +r = 0 has two complex roots a and b then |a| + |b| is..

Let p,q ,r be the elements of R , and r >p>0. If the quadratic equation p(x^2) + qx +r = 0 has two complex roots a and b then |a| + |b| is..

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Let p,q ,r be the elements of R , and r >p>0. If the quadratic equation p(x^2) + qx +r = 0 has two complex roots a and b then |a| + |b| is..

Let p,q ,r be the elements of R , and r >p>0. If the quadratic equation p(x^2) + qx +r = 0 has two complex roots a and b then |a| + |b| is..

1 Answers

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