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`        Let p and q be the roots of the polynomial mx^2 + x(2 - m) + 3. Let m1 and m2 be two values of m satisfying p/q + q/p = 2/3. Determine numerical value of m1/(m2)^2 + m2/(m1)^2.`
6 months ago

```							m1/m2² + m2/m1² = 99Step-by-step explanation:p/q + q/p = 2/3=> (p² + q²)/pq = 2/3=> ( p+q)² - 2pq) /pq = 2/3=> ( p+q)² - 2pq  = 2pq/3=> ( p+q)² -8pq/3 = 0mx² + x(2 - m) + 3p + q  = -(2-m)/m = (m-2)/m  pq = 3/m=>( (m-2)/m)² - 8/m = 0=> m² + 4 - 4m   - m = 0=> m² - 12m + 4 = 0m1 & m2 are rootsm1 + m2 = 12m1.m2 = 4m1/m2² + m2/m1²= (m1³ + m2³)/(m1m2)²m1³ + m2³ = (m1 + m2)³ - 3m1m2(m1+m2) =  (12)³  - 3*4*12 = 12 *12(12 - 1)= 144 * 11(m1m2)² = 4² = 16m1/m2² + m2/m1² = 144 * 11/ 16 = 9 * 11 = 99
```
6 months ago
```							@arun YOU COPIED THE ANSWER FROM BRAINLY.COM... IF I CAN GET THE ANSWER FROM THERE THEN WHAT IS THE USE OF COMING HERE....NOT EXPECTED
```
6 months ago
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