Let f(x)=x^2+b1x+c1, g(x)=x^2+b2x+c2. Real roots of f( x) be A,B and real roots of g(x) be A+D and B+D. Least value of f(x) be -1/4. Least value of g(x) occurs at x=7/2. Find least value of g(z).
Tyler
8 Years agoGrade 12
1 Answer
Arun
8 Years ago
Dear student
least value of f(x) = – (b12 – 4c1)/4 = – ¼
Hence
(b12 – 4c1) = 1
Now
– b2 / 2 = 7/2
– b2 = – 7
Now find roots of F(x) by formula and you will get those two roots.