let f : N --> R be function such that f(1) + 2f(2) + 3f(3) + ............... + nf(n) = n(n+1)f(n), for n>= 2 and f(1) = 1 then find the valueof f(n)and f(5) is ?

First put the value of n=2 and then put f(1)=1 then u will get f(2)=1/4 and similarly If you put n=3 then u will get f(3)=1/6 and similarly f(4)=1/8, f(5)=1/10, so therefore by this we can say that f(n) =1/n for n>_2