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from E to F
let n(E) =m = 4
and n(F) = n =2
since m > n so
no. of onto functions is n^m - C(n,1)*(n-1)^m + C(n,2)*(n-2)^m - …
= 24 – 2C1 (1)4 – 0
= 16 -2 =14
so no. of onto functions from E to F = 14
hope that helps
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