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Let b be a complex number lying on a circle |z|=root2(a) The equation of lines passing through the centre of the circle and making an angle pi/4 with the nrmal at b is? Ans- z=+-(ib^2)(conjugatez)/(2a^2)

Let b be a complex number lying on a circle |z|=root2(a)
 
The equation of lines passing through the centre of the circle and making an angle pi/4 with the nrmal at b is?
 
Ans- z=+-(ib^2)(conjugatez)/(2a^2)

Grade:6

2 Answers

Harsh Patodia IIT Roorkee
askIITians Faculty 907 Points
6 years ago
please recheck the question as there can be many normals at b accordingly there will be lot of lines .
Point b need to be specified to get unique line.
Anil Kumar
9 Points
6 years ago
Z=a(1+i)

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