Let b be a complex number lying on a circle |z|=root2(a) The equation of lines passing through the centre of the circle and making an angle pi/4 with the nrmal at b is? Ans- z=+-(ib^2)(conjugatez)/(2a^2)

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Harsh Patodia · Answer

please recheck the question as there can be many normals at b accordingly there will be lot of lines . Point b need to be specified to get unique line.

Anil Kumar · Answer

Z=a(1+i)

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ADNAN MUHAMMED

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Let b be a complex number lying on a circle |z|=root2(a) The equation of lines passing through the centre of the circle and making an angle pi/4 with the nrmal at b is? Ans- z=+-(ib^2)(conjugatez)/(2a^2)

Let b be a complex number lying on a circle |z|=root2(a)

The equation of lines passing through the centre of the circle and making an angle pi/4 with the nrmal at b is?

Ans- z=+-(ib^2)(conjugatez)/(2a^2)

2 Answers

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Let b be a complex number lying on a circle |z|=root2(a) The equation of lines passing through the centre of the circle and making an angle pi/4 with the nrmal at b is? Ans- z=+-(ib^2)(conjugatez)/(2a^2)

Let b be a complex number lying on a circle |z|=root2(a) The equation of lines passing through the centre of the circle and making an angle pi/4 with the nrmal at b is? Ans- z=+-(ib^2)(conjugatez)/(2a^2)

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Let b be a complex number lying on a circle |z|=root2(a)

The equation of lines passing through the centre of the circle and making an angle pi/4 with the nrmal at b is?

Ans- z=+-(ib^2)(conjugatez)/(2a^2)