let alpha,bita be the root of ax 2 +bx+c=0(a≠0)and gama,sigma be the roots of px 2 +qx+r=0(p≠0),and D 1 ,D 2 be the respective discriminants of these equations.If alpha,bita,gama,sigma are in A.P.,then D 1 :D 2 equals

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Aditya Gupta · Answer

answer is a^2/p^2. simply note that (x-a n )(x-a n+1 )= x-(a n +a n+1 )+a n a n+1 has a discriminant of d^2 where d is the common difference now write ax 2 +bx+c=0 as x 2 +bx/a+c/a=0 and px 2 +qx+r=0 as x 2 +qx/p+r/p=0 so that the discriminant of bothTHESE eqns is d^2 each. or (b/a)^2 – 4c/a= (q/p)^2 – 4r/p and from here we obtain D 1 :D 2 = a^2/p^2

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let alpha,bita be the root of ax 2 +bx+c=0(a≠0)and gama,sigma be the roots of px 2 +qx+r=0(p≠0),and D 1 ,D 2 be the respective discriminants of these equations.If alpha,bita,gama,sigma are in A.P.,then D 1 :D 2 equals

let alpha,bita be the root of ax²+bx+c=0(a≠0)and gama,sigma be the roots of px²+qx+r=0(p≠0),and
D₁,D₂ be the respective discriminants of these equations.If alpha,bita,gama,sigma are in A.P.,then D₁:D_{2 equals}

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let alpha,bita be the root of ax 2 +bx+c=0(a≠0)and gama,sigma be the roots of px 2 +qx+r=0(p≠0),and D 1 ,D 2 be the respective discriminants of these equations.If alpha,bita,gama,sigma are in A.P.,then D 1 :D 2 equals

let alpha,bita be the root of ax2+bx+c=0(a≠0)and gama,sigma be the roots of px2+qx+r=0(p≠0),andD1,D2 be the respective discriminants of these equations.If alpha,bita,gama,sigma are in A.P.,then D1:D2 equals

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let alpha,bita be the root of ax²+bx+c=0(a≠0)and gama,sigma be the roots of px²+qx+r=0(p≠0),and
D₁,D₂ be the respective discriminants of these equations.If alpha,bita,gama,sigma are in A.P.,then D₁:D_{2 equals}