SHAIK AASIF AHAMED
Last Activity: 10 Years ago
Hello student,
The sample space contains 6*6=36 elements
sum of elements on dice from 2,3,4,.,12
p(sum=2) = 1/36 ;p(sum=3) = 2/36 ;p(sum=4) = 3/36
p(sum=5) = 4/36 ;p(sum=6) = 5/36 ;p(sum=7) = 6/36
p(sum=8) = 5/36 ;p(sum=9) = 4/36 ;p(sum=10) = 3/36
p(sum=11) = 2/36 ;p(sum=12) = 1/36
Hence expectation=np
=2(1/36)+3(2/36)+4(3/36)+5(4/36)+6(5/36)+7(6/36)+8(5/36)+9(4/36)+10(3/36)+11(2/36)+12(1/36)
=7
Thanks and Regards
Shaik Aasif
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