Sunil Raikwar
Last Activity: 11 Years ago
[1/(a+b)]+[1/(b+c)]+[1/(c+a)]=7/10
multiply both sides by 7
[7/(a+b)]+[7/(b+c)]+[7/(c+a)]=49/10
[(a+b+c)/(a+b)]+[(a+b+c)/(b+c)]+[(a+b+c)/(c+a)]=49/10
[1+{c/(a+b)}]+[1+{a/(b+c)}]+[1+{c/(a+b)}]=49/10
[c/(a+b)]+[a/(b+c)]+[b/(c+a)]=(49/10)-3
[a/(b+c)]+[b/(c+a)]+[c/(a+b)]=19/10
Thanks & Regards
Sunil Raikwar
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