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Let a,b,,c be real nos. If a+b+c=7 [1/(a+b)]+[1/(b+c)]+[1/(c+a)]=7/10 Then [a/(b+c)]+[b/(c+a)]+[c/(a+b)]=? Please give the solution

Let a,b,,c be real nos.
If a+b+c=7
[1/(a+b)]+[1/(b+c)]+[1/(c+a)]=7/10
Then [a/(b+c)]+[b/(c+a)]+[c/(a+b)]=?
Please give the solution

Grade:11

2 Answers

Parvez ali
askIITians Faculty 47 Points
7 years ago

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Thanks & Regards
Parvez Ali
askIITians Faculty

Sunil Raikwar
askIITians Faculty 45 Points
7 years ago
[1/(a+b)]+[1/(b+c)]+[1/(c+a)]=7/10
multiply both sides by 7
[7/(a+b)]+[7/(b+c)]+[7/(c+a)]=49/10
[(a+b+c)/(a+b)]+[(a+b+c)/(b+c)]+[(a+b+c)/(c+a)]=49/10
[1+{c/(a+b)}]+[1+{a/(b+c)}]+[1+{c/(a+b)}]=49/10
[c/(a+b)]+[a/(b+c)]+[b/(c+a)]=(49/10)-3
[a/(b+c)]+[b/(c+a)]+[c/(a+b)]=19/10

Thanks & Regards
Sunil Raikwar
askIITians faculty

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