its given that ∫ f(x) dx from x=1/3 to 2/3 is equal to 0. We have to find the minimum value of a/b where, a=∫ f’(x)^2 dx ,x=0 to 1 b= ∫( f(x) dx )^2 , x=0 to 1

Question

its given that ∫ f(x) dx from x=1/3 to 2/3 is equal to 0. We have to find the minimum value of a/b where, a=∫ f’(x)^2 dx ,x=0 to 1 b= ∫( f(x) dx )^2 , x=0 to 1

Arun · Answer

Dear Pulkit I think that you have mode some mistake while writig the question.,Please check and repost the question. You. can also attach an image. I will be happy to help you.

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its given that ∫ f(x) dx from x=1/3 to 2/3 is equal to 0. We have to find the minimum value of a/b where, a=∫ f’(x)^2 dx ,x=0 to 1 b= ∫( f(x) dx )^2 , x=0 to 1

its given that

∫ f(x) dx from x=1/3 to 2/3 is equal to 0.
We have to find the minimum value of a/b where,
a=∫ f’(x)^2 dx ,x=0 to 1
b= ∫( f(x) dx )^2 , x=0 to 1

1 Answers

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its given that ∫ f(x) dx from x=1/3 to 2/3 is equal to 0. We have to find the minimum value of a/b where, a=∫ f’(x)^2 dx ,x=0 to 1 b= ∫( f(x) dx )^2 , x=0 to 1

its given that ∫ f(x) dx from x=1/3 to 2/3 is equal to 0.We have to find the minimum value of a/b where,a=∫ f’(x)^2 dx ,x=0 to 1b= ∫( f(x) dx )^2 , x=0 to 1

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its given that

∫ f(x) dx from x=1/3 to 2/3 is equal to 0.
We have to find the minimum value of a/b where,
a=∫ f’(x)^2 dx ,x=0 to 1
b= ∫( f(x) dx )^2 , x=0 to 1