|z1| = |z2|
put z1 = x1 + iy1 and z2 = x2 + iy2
the eqn. will become------>
x1^2 + y1^2 = x2^2 + y2^2 …....................(1)
And fom argument eqn.
it becomes:
tan(pi/2) = (y1/x1 + y2/x2)/(1 -y1y2/x1x2)
or 1 – y1y2/x1x2 = 0
x1x2 = y1y2 ….................................(2)
C opion checking,
(z1 +z2)^2 = » ((x1 +x2) + i(y1 + y2))^2
expanding and using eqn.(1) u will get,
2(x1^2 -y1^2) + 2i(x1 + x2) (y1 + y2)
which is not pure imaginary!
