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In which quadrant does the complex number 1+2i÷(1-i) lie?

In which quadrant does the complex number 1+2i÷(1-i) lie?

Grade:10

2 Answers

Arun
25750 Points
6 years ago
Multiply by (1+i) in numerator and denominator both
(1+2i)(1+i)/(1-i)(1+i)
= (1+i+2i -2)/1+1
= (-1 + 3i)/2
As we see,
Real parts is negative while imaginary parts is positive
Hence this will lie in 4th Quadrant
Beyond the Horizon
9 Points
5 years ago
multiply and divide the complex number with (1+i), we get
(-1+3i)/2
here, real part is on negative x axis and imaginary part on positive y axis.
so the number lies in quadrant 2

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