Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

In the listed image can you tell me how beta*gamma = 2 ….. . . .. ??

In the listed image can you tell me how beta*gamma = 2 ….. . . .. ??

Question Image
Grade:12th pass

5 Answers

Ajay
209 Points
4 years ago
The value of gamma is not clear in image, could you mention what gamma us equal to...................
Anshuman Mohanty
27 Points
4 years ago
Yes sorry..... . . . .it is not so clear.. ok the values are beta = α + α^2 + α^4 and gamma = α^3 + α^5 + α^7
Anshuman Mohanty
27 Points
4 years ago
PLease answer.  . . .. ….................................................................................
Ajay
209 Points
4 years ago
The value of gamma is still not correct, either printing mistake or you gave me wrong value.
The correct value of gamma is below
\beta =\alpha +{ \alpha }^{ 2 }+{ \alpha }^{ 4 }\quad and\quad \gamma \quad =\quad { \alpha }^{ 3 }+{ \alpha }^{ 5 }+{ \alpha }^{ 6 }\\ now\quad 1,\quad \alpha ,\quad { \alpha }^{ 2 },{ \alpha }^{ 4 },\quad { \alpha }^{ 3 },{ \alpha }^{ 5 },{ \alpha }^{ 6 }\quad are\quad 7th\quad roots\quad of\quad unity\\ we\quad have\quad 1+\alpha +{ \alpha }^{ 2 }+{ \alpha }^{ 3 }+{ \alpha }^{ 4 }+{ \alpha }^{ 5 }+{ \alpha }^{ 6 }\quad =\quad 0\quad -------------(1)\\ and\quad { \alpha }^{ 7 }\quad =\quad 1,\quad { \alpha }^{ 8 }\quad =\quad { \alpha },\quad { \alpha }^{ 9 }\quad =\quad { \alpha }^{ 2 }\quad etc----------(2)\\ \beta \gamma \quad =\quad { \alpha }^{ 4 }+{ \alpha }^{ 6 }+{ \alpha }^{ 7 }+{ \alpha }^{ 5 }+{ \alpha }^{ 7 }+{ \alpha }^{ 8 }+{ \alpha }^{ 7 }+{ \alpha }^{ 9 }+{ \alpha }^{ 10 }
from\quad (2)\\ \quad \quad \quad =\quad { \alpha }^{ 4 }+{ \alpha }^{ 6 }+1+{ \alpha }^{ 5 }+1+{ \alpha }+1+{ \alpha }^{ 2 }+{ \alpha }^{ 3 }\\ \quad \quad \quad =\quad 1+\alpha +{ \alpha }^{ 2 }+{ \alpha }^{ 3 }+{ \alpha }^{ 4 }+{ \alpha }^{ 5 }+{ \alpha }^{ 6 }+2\\ \quad \quad \quad \quad \quad use\quad value\quad from\quad eq\quad (1)\\ \quad \quad =\quad 2
Anshuman Mohanty
27 Points
4 years ago
Thankyou so much.............................  …......................................................................!

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free