Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Live 1-1 coding classes to unleash the creator in your Child
In ∆ PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P
Dear StudentIn a given triangle PQR, right angled at Q, the following measures are PQ = 5 cmPR + QR = 25 cmNow let us assume, QR = xPR = 25-QRPR = 25- xAccording to the Pythagorean Theorem,PR^2= PQ^2+ QR^2Substitute the value of PR as x(25- x) ^2= 52+ x^225^2+ x^2–50x = 25 + x^2625 + x^2-50x -25–x^2= 0-50x = -600x= -600/-50x = 12 = QRNow, find the value of PRPR = 25- QRSubstitute the value of QRPR = 25-12PR = 13Now, substitute the value to the given problemThanks
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -