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In ∆ PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P In ∆ PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P
Dear StudentIn a given triangle PQR, right angled at Q, the following measures are PQ = 5 cmPR + QR = 25 cmNow let us assume, QR = xPR = 25-QRPR = 25- xAccording to the Pythagorean Theorem,PR^2= PQ^2+ QR^2Substitute the value of PR as x(25- x) ^2= 52+ x^225^2+ x^2–50x = 25 + x^2625 + x^2-50x -25–x^2= 0-50x = -600x= -600/-50x = 12 = QRNow, find the value of PRPR = 25- QRSubstitute the value of QRPR = 25-12PR = 13Now, substitute the value to the given problemThanks
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