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In how many ways , we can choose two teams of mixed double for a tennis tournament from four couples such that if any couple participates , then it is in the same team Please provide well explained solution

Harsh , 7 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear Harsh
 
Case-1
No couple is chosen
2* 4C2
 
Case-2
When only 1 couple is chosen
4C1 *3C1 * 2C1
 
Case-3
When two couples are chosen
4C2
 
Hebce total number of ways
= 2*4C2 + (4C1*3C1*2C1) + 4C2
 = 42
 
Regards
Arun (askIITians forum expert)

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