 ×     #### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
In ∆ ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine: (i) sin A, cos A (ii) sin C, cos C

```
one month ago Anand Kumar Pandey
1372 Points
```							Dear StudentGiven:​AB = 24 cm and BC = 7 cmIn a given triangle ABC, right angled at B =∠B = 90°By applying Pythagoras theorem,In a right- angled triangle, the squares of the hypotenuse side is equal to the sum of the squares of the[page1image1641698352]other two sides.we getAC^2=AB^2+BC^2AC^2= (24)^2+7^2AC^2= (576+49)AC^2= 625cm^2AC =√625 = 25 Therefore, AC = 25 cm(i) To find Sin (A), Cos (A)We know that sine (or) Sin function is the equal to the ratio of length of the opposite side to the hypotenuse side. So it becomesSin (A) = Opposite side /Hypotenuse = BC/AC = 7/25Cosine or Cos function is equal to the ratio of the length of the adjacent side to the hypotenuse side and it becomes,Cos (A) = Adjacent side/Hypotenuse = AB/AC = 24/25(ii) To find Sin (C), Cos (C) Sin (C) = AB/AC = 24/25 Cos (C) = BC/AC = 7/25Thanks
```
one month ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Algebra

View all Questions »  ### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions