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If z = reiΘ , then the value of |eiz| is equal to-\te-rcosΘ\tercosΘ\te-rsinΘ\tersinΘPlease answer quick....

Mohit Soni , 7 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear Mohit
 
I have written theta as @ because of simplicity in writing.
 
e^i(re^i@)
= e ^i(r cos@ + i sin@)
= e ^ (i r cos@ - sin@)
= e ^-sin@ *  e^i r cos@
Now |e^iz| = e^-sin@  * |e^i r cos@|
= e-sin @        (because |ei r cos@| = 1)
Hence option C is correct.
 
 
Regards
Arun (askIITians forum expert)

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