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Grade 12th passAlgebra

if z=-1then the principal value of the Arg(z^2/3) is equal to

Profile image of Adarsh tiwari
8 Years agoGrade 12th pass
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1 Answer

Profile image of Arun
8 Years ago
z= –1
we can write z = cos(pi) + i sin(pi) = ei\pi
now z2/3 = ei 2\pi/3
hence arg(z2/3) = 2\pi/3
hope it helps

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