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Grade 12Algebra

if X+y+z=1,

minimum value of xy(x+y)^2+yz(y+z)/^2+zx(z+x)^2

wherex,y,z are positive real numbers.

Profile image of NANDA
12 Years agoGrade 12
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1 Answer

Profile image of mycroft holmes
12 Years ago
The expression can be made as small as we please. If e is a very small positive number let x=y=e, then z=1-2e. Then the expression is of the order of e. All we can say is that the lower bound is zero