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if X+y+z=1, minimum value of xy(x+y)^2+yz(y+z)/^2+zx(z+x)^2 wherex,y,z are positive real numbers.

if X+y+z=1,


minimum value of xy(x+y)^2+yz(y+z)/^2+zx(z+x)^2


wherex,y,z are positive real numbers.

Grade:12

1 Answers

mycroft holmes
272 Points
7 years ago
The expression can be made as small as we please. If e is a very small positive number let x=y=e, then z=1-2e. Then the expression is of the order of e. All we can say is that the lower bound is zero

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