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Grade: 11
        
If xlog y=log x then show that dy​/dx= y[1-logxlogy]/x(log2x)
one month ago

Answers : (1)

Aditya Gupta
1808 Points
							
hey yamini
take log on both sides
log xlog y= log(log x)
logy*log = log(log x)
differentiate both sides wrt x
(1/y)*(y’)*log x + logy*1/x= 1/xlog x
so, y’=  dy​/dx= y[1 – logxlogy]/x(log2x)
kindly approve :)
one month ago
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