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if (x+iy)(p+iq)=(x^2+y^2)i,then, a)p=x,q=y b)p=x^2,q=y^2 c)x=p,y=p d)x=-q,y=p
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On expansion of LHS(xp-yq) + (xq+yp)i = (x^2+y^2)iOn comparing real partsx = yq/pIn comparison of imaginary partsxq+ yp = x^2+y^2Put tge value of x = yq/py = pHence x = q
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