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IF x^4+1/x^4=47 , find the value of (x-1/x)^2. PLEASE ANSWER THIS QUESTION ASAP

RONAV ROY , 3 Years ago
Grade 9
anser 1 Answers
Rashi Mishra

Last Activity: 3 Years ago

Adding 2 on both sides
x4+1/x4+2=47+2
x4+1/x4+2(x4)(1/x4)=49 [a2+b2+2ab=(a+b)2]
(x2+1/x2)2=72
x2+1/x2=7
subtracting 2 on both sides
x2+1/x2-2=7-2
x2+1/x2-2(x)(1/x)=5 [a2+b2-2ab=(a-b)2]
(x-1/x)2=5

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