Grade 6Algebra
if x=2 y=1.15 z=0.01 then the value of xz(x2+y2) is
if x=2 y=1.15 z=0.01 then the value of xz(x2+y2) is
1 Answer
Arun
Dear student
XZ (X² + Y²)
2*0.01 ( 2² + 1.15²)
= 2.02 (4 + 2.4025)
= 2.02 * 6.4025
= 12.933050
Regards
Arun (askIITians forum expert)
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