if x=2 y=1.15 z=0.01 then the value of xz(x2+y2) is

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Arun · Answer

Dear student XZ (X² + Y²) 2*0.01 ( 2² + 1.15²) = 2.02 (4 + 2.4025) = 2.02 * 6.4025 = 12.933050 Regards Arun (askIITians forum expert)

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if x=2 y=1.15 z=0.01 then the value of xz(x2+y2) is

if x=2 y=1.15 z=0.01 then the value of xz(x2+y2) is

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if x=2 y=1.15 z=0.01 then the value of xz(x2+y2) is

if x=2 y=1.15 z=0.01 then the value of xz(x2+y2) is

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