If x 2 +x+1=0, then the value of [x 3 + 1/x 3 ] 3 is A) -8 B) -1 C) 0 D) 8

Question

Anshuman Chandel · Answer

x=omega (cube root of unity) ans is 8

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If x 2 +x+1=0, then the value of [x 3 + 1/x 3 ] 3 is A) -8 B) -1 C) 0 D) 8

If x²+x+1=0, then the value of [x³+ 1/x³]³is

A) -8

B) -1

C) 0

D) 8

1 Answers

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If x 2 +x+1=0, then the value of [x 3 + 1/x 3 ] 3 is A) -8 B) -1 C) 0 D) 8

If x2+x+1=0, then the value of [x3 + 1/x3]3 is A) -8 B) -1 C) 0 D) 8

1 Answers

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If x²+x+1=0, then the value of [x³+ 1/x³]³is

A) -8

B) -1

C) 0

D) 8