If x 2 +3x+3=0 and ax 2 +bx+1=0 ,(a,b belong to rational) have a common root, then value of (3a+b) is equal to : (A) 1/3 (B) 1 (C) 2 (D) 4

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Arun · Answer

1st equation has D 0 hence it has both roots imaginary Hence both equations have oth roots common so 1/a = 3/b =3/1 a = 1/3 b = 1 hence a/b = 1/3

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If x 2 +3x+3=0 and ax 2 +bx+1=0 ,(a,b belong to rational) have a common root, then value of (3a+b) is equal to : (A) 1/3 (B) 1 (C) 2 (D) 4

If x²+3x+3=0 and ax²+bx+1=0 ,(a,b belong to rational) have a common root, then value of (3a+b) is equal to :
(A) 1/3
(B) 1
(C) 2
(D) 4

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If x 2 +3x+3=0 and ax 2 +bx+1=0 ,(a,b belong to rational) have a common root, then value of (3a+b) is equal to : (A) 1/3 (B) 1 (C) 2 (D) 4

If x2+3x+3=0 and ax2+bx+1=0 ,(a,b belong to rational) have a common root, then value of (3a+b) is equal to :(A) 1/3(B) 1(C) 2(D) 4

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If x²+3x+3=0 and ax²+bx+1=0 ,(a,b belong to rational) have a common root, then value of (3a+b) is equal to :
(A) 1/3
(B) 1
(C) 2
(D) 4