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If we put value of n in 4 n -1 we get that each term is devisible by 3 but if there is any other way to prove that it is divisible by 3 like how should we do it in Subjective exam??

If we put value of n in 4-1 we get that each term is devisible by 3 but if there is any other way to prove that it is divisible by 3 like how should we do it in Subjective exam??

Grade:12

2 Answers

SAHIL
3783 Points
5 years ago
i am very very sorry but no such other method or trick is available. try to solve such questions more an more so that you become perfect in such questions
best of luck for future
thanks and please APPROVE my answer
with best wishes AND regards sahil
Hardeep Singh
10 Points
5 years ago
Well sorry but now I got the answer myself
In 4n-1 assume 4=x
So we get x​​​​^n-1 of which there must exist a factor x-1
So there must be a factor of above 4-1=3 so
4n-1 must have a factor 3 so it must be devisible by 3

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