If we put value of n in 4 n -1 we get that each term is devisible by 3 but if there is any other way to prove that it is divisible by 3 like how should we do it in Subjective exam??

Question

SAHIL · Answer

i am very very sorry but no such other method or trick is available. try to solve such questions more an more so that you become perfect in such questions best of luck for future thanks and please APPROVE my answer with best wishes AND regards sahil

Hardeep Singh · Answer

Well sorry but now I got the answer myself In 4 n -1 assume 4=x So we get x​​​​^n-1 of which there must exist a factor x-1 So there must be a factor of above 4-1=3 so 4 n -1 must have a factor 3 so it must be devisible by 3

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If we put value of n in 4 n -1 we get that each term is devisible by 3 but if there is any other way to prove that it is divisible by 3 like how should we do it in Subjective exam??

If we put value of n in 4ⁿ-1 we get that each term is devisible by 3 but if there is any other way to prove that it is divisible by 3 like how should we do it in Subjective exam??

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If we put value of n in 4 n -1 we get that each term is devisible by 3 but if there is any other way to prove that it is divisible by 3 like how should we do it in Subjective exam??

If we put value of n in 4n -1 we get that each term is devisible by 3 but if there is any other way to prove that it is divisible by 3 like how should we do it in Subjective exam??

2 Answers

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If we put value of n in 4ⁿ-1 we get that each term is devisible by 3 but if there is any other way to prove that it is divisible by 3 like how should we do it in Subjective exam??