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If w is the cube √ of unity then prove that (1-w)^6=27

Nitya , 7 Years ago
Grade 12th pass
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Last Activity: 7 Years ago

It`s value is equal to -27, as by using Pascal triangle we can expand it as 1-6w+15w^2-20w^3 +15w^4 -6w^5 + w^6 and if u solve this u will get the value as -27

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