if third term of gp is 2/9 and sum of infinite terms is 3/2 then find the series

Question

Shailendra Kumar Sharma · Answer

ar2 = 2/9a/(1-r) = 3/2dividing the equtions r2(1-r)= 4/27=> r=2/3and a=9/4*(2/9)a=1/2so series is ½, 1/3, 2/9, 4/27...

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if third term of gp is 2/9 and sum of infinite terms is 3/2 then find the series

if third term of gp is 2/9 and sum of infinite terms is 3/2 then find the series

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if third term of gp is 2/9 and sum of infinite terms is 3/2 then find the series

if third term of gp is 2/9 and sum of infinite terms is 3/2 then find the series

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