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If the sum of n terms of an A.P. is n2, then its nth term is (a) 2n – 1 (b) 2n + 1 (c) n2 – 1 (d) 2n – 3

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2 months ago

```							Dear student sₙ =n/2{2a+(n-1)d}where a =first term ,d =common difference ,n =no of terms sₙ=n/2(a+l)l =last term sₙ=n²putting n= 1 , s₁=1²=1s₁ is sum of first term which is equal to first terma₁=s₁ =1now putting n=2 in sₙs₂ =2²=4s₂ is sum of first two terms soa₁+a₂=s₂=41 + a₂=4a₂=4-1=3now a₁=1,d=a₂-a₁=3-1=2,n=n,aₙ=?we have formula of nth term of APaₙ=a+(n-1)d=1+(n-1)2=1+2n-2=(2n-1)
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2 months ago
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