Vikas TU
Last Activity: 4 Years ago
Dear student
sₙ =n/2{2a+(n-1)d}
where a =first term ,d =common difference ,n =no of terms
sₙ=n/2(a+l)
l =last term
sₙ=n²
putting n= 1 , s₁=1²=1
s₁ is sum of first term which is equal to first term
a₁=s₁ =1
now putting n=2 in sₙ
s₂ =2²=4
s₂ is sum of first two terms so
a₁+a₂=s₂=4
1 + a₂=4
a₂=4-1=3
now a₁=1,d=a₂-a₁=3-1=2,n=n,aₙ=?
we have formula of nth term of AP
aₙ=a+(n-1)d
=1+(n-1)2
=1+2n-2
=(2n-1)