If the roots of the given equation 2x^2+3(A-2)x+ A+4=0 be equal in magnitude but opposite in sign, then A=
(a)1
(b)2/3
(c)3
(d)2

Question

If the roots of the given equation 2x^2+3(A-2)x+ A+4=0 be equal in magnitude but opposite in sign, then A= (a)1 (b)2/3 (c)3 (d)2

Arun · Answer

Dear student hence if one root is t and other root will be – t hence sum of oots = t + (- t) = – 3(A – 2)/2 - 3(A- 2) /2 = 0 A – 2 = 0 A = 2 Jope it helps

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If the roots of the given equation 2x^2+3(A-2)x+ A+4=0 be equal in magnitude but opposite in sign, then A= (a)1 (b)2/3 (c)3 (d)2

If the roots of the given equation 2x^2+3(A-2)x+ A+4=0 be equal in magnitude but opposite in sign, then A=
(a)1
(b)2/3
(c)3
(d)2

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If the roots of the given equation 2x^2+3(A-2)x+ A+4=0 be equal in magnitude but opposite in sign, then A= (a)1 (b)2/3 (c)3 (d)2

If the roots of the given equation 2x^2+3(A-2)x+ A+4=0 be equal in magnitude but opposite in sign, then A=(a)1(b)2/3(c)3(d)2

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If the roots of the given equation 2x^2+3(A-2)x+ A+4=0 be equal in magnitude but opposite in sign, then A=
(a)1
(b)2/3
(c)3
(d)2