Ankit Sharma
Last Activity: 3 Years ago
Given: |2x-1|

X+1
Firstly break the modulus at its breaking point.
2x-1=0
X=1/2.
NOW,
For, X

1/2, 2X-1 is a negative so,
modulus open with negative sign,equation is like that,
-2x+1

X+1
On solving we get, X

0
Taking intersection with Above applied conditions we get 0

X
1/2 .... (eqn 1)
Now, similarly for X
½Modules opens with +sign.
So we get here X

2
AGAIN Taking intersection with just above applied condition
We get
1/2
X
2 ...... (eqn 2) Now take union of above two equation
We get 0
X
2 and this is final answer Alternative approach :::
Just draw graph of above functions then judge.