Flag Algebra> If the real number x satisfying the inequ...
question mark

If the real number x satisfying the inequality 2x-1

Khalid salim attar , 3 Years ago
Grade 12
anser 1 Answers
Ankit Sharma

Last Activity: 3 Years ago

Given: |2x-1| \leq  X+1
Firstly break the modulus at its breaking point. 
2x-1=0
X=1/2.
NOW,
For, X \leq 1/2, 2X-1 is a negative so, modulus open with negative sign,equation is like that,
-2x+1\leq \  X+1
On solving we get, X\geq0
Taking intersection with Above applied conditions we get 0\leq X\leq1/2 .... (eqn 1)
 
Now, similarly for X\geq ½
Modules opens with +sign. 
So we get here X\leq 2
AGAIN Taking intersection with just above applied condition 
We get 1/2 \leq X\leq 2          ...... (eqn 2)
      Now take union of above two equation 
We get 0\leq X\leq2 and this is final answer
Alternative approach :::
Just draw graph of above functions then judge. 
 

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...