Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

If the real number x satisfying the inequality 2x-1

If the real number x satisfying the inequality 2x-1

Question Image
Grade:12

1 Answers

Ankit Sharma
26 Points
one month ago
Given: |2x-1| \leq  X+1
Firstly break the modulus at its breaking point. 
2x-1=0
X=1/2.
NOW,
For, X \leq 1/2, 2X-1 is a negative so, modulus open with negative sign,equation is like that,
-2x+1\leq \  X+1
On solving we get, X\geq0
Taking intersection with Above applied conditions we get 0\leq X\leq1/2 .... (eqn 1)
 
Now, similarly for X\geq ½
Modules opens with +sign. 
So we get here X\leq 2
AGAIN Taking intersection with just above applied condition 
We get 1/2 \leq X\leq 2          ...... (eqn 2)
      Now take union of above two equation 
We get 0\leq X\leq2 and this is final answer
Alternative approach :::
Just draw graph of above functions then judge. 
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free