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If the point (a, -a) lies inside the circ|e x2+y2-4x+2y-8 = 0, then values of parameter a, are (1) a € [-1, 4] (2) a € (-1,4) (3) a € (1, 4) (4) None €=belongs to

Nitin Kumar , 9 Years ago
Grade 11
anser 1 Answers
Vikas TU
If the point (a, -a) lies inside the circ|e x2+y2-4x+2y-8 = 0 then the circle e should be less than zero.
Therefore, substituing the point to the circle, we get,
a^2 + a^2 - 4a – 2a – 8 less than zero
on solving we get
a belongs to (-1,4)
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Last Activity: 9 Years ago
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