Vikas TU
Last Activity: 8 Years ago
The Range of sinx is [-1,1]
.i.e
-1
-1 3x
Check conditions on boundary,
for minimum of sinx
the eqn. becomes,
when sin x= -1
=> -a + 2 = 2a – 8
=> 10 = 3a
a = 10/3 = 3.33 (approx)
when sinx = 1
eqn. becomes,
a -2 = 2a – 8
a = -2 + 8
a = 6
therfore range of a is,
3.33