IF THE CONDITIONAL PRODUCTS OF THREE NUMBERS IN G

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IF THE CONDITIONAL PRODUCTS OF THREE NUMBERS IN G.P IS 216 AND SUM OF THEIR PRODUCTS IN PAIRS IS 156 THEN FIND SUM OF THREE NUMBERS

Arun · Accepted Answer

Dear student Let a/r , a , ar are in GPA/C to question, (a/r ) × a × ar = 216a³ = 216a³ = (6)³ a = 6 again, sum of their products in pair = 156 (a/r ) × a + a × ar + ar × (a/r) = 156 a²/r + a²r + a² = 15636/r + 36r + 36 = 156 36( 1/r + r + 1) = 156 3(r² + r + 1) = 13r 3r² + 3r + 3 - 13r = 03r² -10r + 3 = 03r² - 9r - r + 3 = 0r = 3 and 1/3so, numbers are 6/3, 6 , 6×3 => 2, 6, 18 numbers are 6×3 , 6 , 6/3 => 18, 6, 2RegardsArun (askIITians forum expert)

Algebra> IF THE CONDITIONAL PRODUCTS OF THREE NUMB...

IF THE CONDITIONAL PRODUCTS OF THREE NUMBERS IN G.P IS 216 AND SUM OF THEIR PRODUCTS IN PAIRS IS 156 THEN FIND SUM OF THREE NUMBERS

YAMINIVARSHITHA , 6 Years ago

Arun

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Algebra> IF THE CONDITIONAL PRODUCTS OF THREE NUMB...

IF THE CONDITIONAL PRODUCTS OF THREE NUMBERS IN G.P IS 216 AND SUM OF THEIR PRODUCTS IN PAIRS IS 156 THEN FIND SUM OF THREE NUMBERS

YAMINIVARSHITHA , 6 Years ago

Arun

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