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`        If the average of 20 different positive integers is 20, then the greatest possible number among these 20 numbers can be:(a) 210(b) 200(c) 190(d) 180`
6 months ago

## Answers : (2)

1714 Points
```							obviously the first 19 numbers would have to be the least possible and different from each other in order for the 20th to be maximum.so let 19 of the nos be 1, 2, 3, …., 19let the max no be x.now avg= sum/20= 20or sum= 400or x+(1+2+...+19)= 400but 1+2+...+19= 19*20/2= 190so x= 400 – 190x= 210kindly approve :)
```
6 months ago
Arun
22958 Points
```							Dear student greatest number = 400 – ( 19 lowest terms ) = 400 – (1 + 2 + 3 + ….......+19)  = 400 – 19*20/2 = 400 – 210 =190 Hope it helps RegardsArun
```
6 months ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions