If sinA+sinB=1/2 and cosA+cosB=1/4 then prove that tan(A+B)/2=0

Question

Anish Singhal · Answer

Sin A + sin B=1/2
Sin (A+B)=1/2
Cos A+ cos B =1/4
Cos (A+B)=1/4
Sin (A+B)/cos (A+B)=1/2×4/1=2
Sin (A+B)/cos (A+B)=tan(A+B)=2
Now dividing both sides by 2,we have
Tan(A+B)/2=2/2
Tan(A+B)/2=1

Tan (A+B)=1

Arun · Answer

Dear Anish You have done this wrong sinA + sinB = ½ 2 sin(A + B)/2 * cos (A – B)/2= ½ Now cos A + cos B = ¼ 2 cos(A + B)/2 * cos (A – B)/2 = ¼ Now divide both the equations tan (A + B)/2 = 2 Regards Arun

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If sinA+sinB=1/2 and cosA+cosB=1/4 then prove that tan(A+B)/2=0

If sinA+sinB=1/2 and cosA+cosB=1/4 then prove that tan(A+B)/2=0

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