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If sinA+sinB=1/2 and cosA+cosB=1/4 then prove that tan(A+B)/2=0
Sin A + sin B=1/2Sin (A+B)=1/2Cos A+ cos B =1/4Cos (A+B)=1/4Sin (A+B)/cos (A+B)=1/2×4/1=2Sin (A+B)/cos (A+B)=tan(A+B)=2Now dividing both sides by 2,we haveTan(A+B)/2=2/2Tan(A+B)/2=1Tan (A+B)=1
Dear Anish You have done this wrong sinA + sinB = ½2 sin(A + B)/2 * cos (A – B)/2= ½ Now cos A + cos B = ¼2 cos(A + B)/2 * cos (A – B)/2 = ¼ Now divide both the equations tan (A + B)/2 = 2 RegardsArun
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