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if s1,s2,s3 are the sum of first n natural numbers their squares their cubes respectively then s3{1+8s1}/s 2 2 is equal to

if     s1,s2,s3 are the sum of first n natural numbers their squares their cubes respectively then s3{1+8s1}/s22is equal to 

Grade:11

1 Answers

ashish
22 Points
7 years ago
S3(1+8S1)/S2.S2=.6.6n2(n+1)2 [1+4n(n+1)]/4.n.(n+1).(2n+1).n.(n+1).(2n+1)
    By solving above ,We get
                          =36/9
 
                           =4
 

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