If r = x(a×b)+y(b×c)+z(c×a) and [abc]= 1/3 then x+y+z=

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Saurabh Koranglekar · Answer

Dear student The mention of xyz is it a dot product? Please confirm or kindly attach an image of the source of the question Regards

Vikas TU · Answer

Dear student Question is not clear Please upload an image. We will happy to help you. Good luck Cheers

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If r = x(a×b)+y(b×c)+z(c×a) and [abc]= 1/3 then x+y+z=

If r = x(a×b)+y(b×c)+z(c×a) and [abc]= 1/3 then x+y+z=

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If r = x(a×b)+y(b×c)+z(c×a) and [abc]= 1/3 then x+y+z=

If r = x(a×b)+y(b×c)+z(c×a) and [abc]= 1/3 then x+y+z=

2 Answers

Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

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