MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11
        
If pth , qth, rth term of an AP are in GP , then common ratio of this GP is 
  1. (p-q)/(q-r)
  2. (q-r)/(p-q)
  3. pqr
  4. none of this
one year ago

Answers : (2)

moumi roy
91 Points
							
as this is in AP 2q=p+r----eq(1)
as in GP q=p.c & r=p*c2 where  c=common difference,
putting in eq(1) 2*p.c=p+p*c2 hence c^2+1-2c=0 or ( c-1)2=0 so c=1
frm(1) p-q=q-r or (p-q)/(q-r)=1=c or(q-r)/(p-q)=1=c so both can be the answer
 
one year ago
Tushar Avhad
19 Points
							Given that.  pth ,qth,rth. Terms of an ap are in gp..therefore    a+(q-1)d.            a+(r-1)d--------------------     =  -----------------(since they are     a+(p-1)d.            a+(q-1)d.      Are in gp)Now,Let    a+(q-1)d.            a+(r-1)d--------------------     =  -----------------=  k   a+(p-1)d.              a+ (q-1)dBy theorem on equal ratiosWe geta+ qd-d -(a+rd-d)----------------------------=ka+pd-d-(a+qd-d)On simplifying we get        qd-rd------------------=k       pd-qd d(q-r)----------=kd(p-q)  Therefore    (q-r)-------------=k    (P-q)Hope this will help u
						
11 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Get Extra Rs. 3,180 off

COUPON CODE: BCK2SKOOL


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 466 off

COUPON CODE: BCK2SKOOL

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details