Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
        if p,q,r,s are positive integers such that the arthemetic mean of the roots of the equation x^2-px+q^2 and the geometric mean of the roots of the equationx^2-rx+s^2  are equal, then the values of ,q,r,s can be????????
10 months ago

Rohit Kumar
20 Points
							Roots of  $x^2-px+q^2=0$ are $\frac{p+\sqrt(p^2-4q^2)}{2}$ and $\frac{p-\sqrt(p^2-4q^2)}{2}$ . Arithemetic mean of the roots is $\frac{p}{2}$.Roots of  $x^2-rx+s^2=0$ are $\frac{r+\sqrt(r^2-4s^2)}{2}$ and $\frac{r-\sqrt(r^2-4s^2)}{2}$ . Geometric mean of the roots is $s$.By given condition  A.M. = G.M. this implies $p = 2.s$ .So we can take any integer value of $q,r,s$ and value of $p$ = 2*value of $s$.

10 months ago
Rohit Kumar
20 Points
							Correction in final answer : .$s$ = 2*value of $p$ and value of $q,r,s$So we can take any positive integer value of

10 months ago
Think You Can Provide A Better Answer ?

Other Related Questions on Algebra

View all Questions »

COUPON CODE: SELF10

Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions

Post Question