If p/a+q/b+r/c =1 and a/p+b/q+c/r =0 then (p/a)^2+(q/b)^2+(c/r)^2 =?

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Vijay Mukati · Answer

Dear Student, Using (a+b+c) 2 = a 2 + b 2 + c 2 + 2(ab+bc+ca). final answer will be -2(pqr/abc). Thanks.

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If p/a+q/b+r/c =1 and a/p+b/q+c/r =0 then (p/a)^2+(q/b)^2+(c/r)^2 =?

If p/a+q/b+r/c =1 and a/p+b/q+c/r =0 then (p/a)^2+(q/b)^2+(c/r)^2 =?

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If p/a+q/b+r/c =1 and a/p+b/q+c/r =0 then (p/a)^2+(q/b)^2+(c/r)^2 =?

If p/a+q/b+r/c =1 and a/p+b/q+c/r =0 then (p/a)^2+(q/b)^2+(c/r)^2 =?

1 Answers

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